Question

Graphing a parabola of the form y=ax squared 2

Answer 1

The graph of the parabola given by the equation:

`y=(1)/(4)x^2`

has a vertex when y=0 which happens iff

`\begin{gathered} (1)/(4)x^2=0 \\ x^2=0 \\ x=0 \end{gathered}`

Therefore the graph is:

The vertex has coordinates (0,0). Now, two points to the left of the vertex that are on the parabola have coordinates (-2,1) and (-4,4). Two points that are to the right of the parabola have coordinates