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What is the axis of symmetry for f(x) = x2 + 4x + 6? A. x= -4B. X= -2C. X = 2D X = 3

User MiguelB
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Answer:

Step by step explanation:

In order to find the axis of symmetry, we will have to find the x-value of the vertex


\text{Vertex = }\lbrack(-b)/(2a),\text{ f(}(-b)/(2a))\rbrack
x^2\text{ + 4x +6}

a = 1

b = 4

c = 6


\text{Vertex = }\lbrack(-4)/(2),f((-4)/(2))\rbrack
Vertex=\lbrack-2,f(-2)\rbrack\text{ }

We have found the x-value of the vertex which is -2

Line/axis of symmetry is x=-2

User Bubble Bub
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