14.2k views
4 votes
The equation d=16t^2 gives the distance in feet that a golf ball falls in t seconds.How many seconds will it take the gol to drop to the ground from a height of 4 feet?64 feet?

1 Answer

1 vote

We are given the following function of distance in terms of time:


d=16t^2

Where:


\begin{gathered} d=\text{ distance} \\ t=\text{ time} \end{gathered}

We are asked to determine the time when the distance is 4ft. To do that we will solve for "t". First, we will divide both sides by 16:


(d)/(16)=t^2

Now, we take the square root to both sides:


\sqrt{(d)/(16)}=t

Simplifying we get:


(1)/(4)√(d)=t

Now, we substitute the value of the distance:


(1)/(4)√(4)=t

Solving the operations:


\begin{gathered} (1)/(2)=t \\ \\ 0.5=t \end{gathered}

Therefore, the time is 0.5

The same procedure is used to determine the time for 64 feet.

User MHG
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories