Question

triangle PQR with vertices P(6,-6) Q(9,-7) and R(7,-4) what is the area in square units of triangle PQR

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

P(6,-6)

Q(9,-7)

R(7,-4)

A = ?

Step 02:

To solve the exercise we must know the length of the sides.To solve the exercise we must know the length of the sides.

A = (b * h) / 2

side PR = b

side PQ = h

`d\text{ = }\sqrt[]{(x2-x1)^(2)+(y2-y1)^(2)}`
`b\text{ = }\sqrt[]{(7-6)^2+(-4-(-6))^2}`
`b=\text{ }\sqrt[]{1+4}=\sqrt[]{5}=2.236`
`\begin{gathered} h\text{ = }\sqrt[]{(9-6)^(2)+(-7-(-6))^(2)} \\ h\text{ = }\sqrt[]{9+1}=\sqrt[]{10}=3.162 \end{gathered}`

Step 03:

A = (2.236*3.162) / 2 = 3.5355

The answer is:

3.54 ft²