Question

hentIf TR = 11 ft, find the length of PS.IfР P.TentR16d ArcsSnd ArcsRound to 2 decimal places.and Arcs

Answer 1

This is a length of arc problem.

The formula for finding the length of an arc is:

`(\theta)/(360)*2\pi r`

r=TR=PT=11ft

`\begin{gathered} (\theta)/(360)*2\pi r \\ r=11ft \\ \theta=164^o \end{gathered}`
`\begin{gathered} (164)/(360)*2\pi(11) \\ =(164)/(360)*2*3.14*11 \\ =31.4698ft \\ =31.47ft(to\text{ 2 decimal places)} \end{gathered}`

The final answer is 31.47ft.