Given:
![(x^2+8x+12)/(x+2)](https://img.qammunity.org/2023/formulas/mathematics/college/f6hg1fkx1shawta2h3npp03271d1mmw5uk.png)
Let's divide the polynomials.
To divide, let's factorize the polynomial in the numerator.
Factorize using the AC method.
Find a pair of numbers whose product is 12 and whose sum is 8.
Thus, we have the numbers:
2 and 6
The factors of the polynomial in the numerator are:
(x+2) and (x+6)
We have:
![((x+2)(x+6))/(x+2)](https://img.qammunity.org/2023/formulas/mathematics/college/5pk9f6ahmkf2ksoc502wg2oalk7ppkmblz.png)
Now, cancel the common factors:
Therefore, the quotient after dividing the polynomials is = x + 6
ANSWER:
![x+6](https://img.qammunity.org/2023/formulas/mathematics/college/5abvkjkvq6glx2isw0u1u35i52xsig7w2y.png)