Question

Enter the equation of the circle with the given center and radius. Center: (7,0); radius: 3 The equation is

Answer 1

Given data:

The given coordinate of centre of the circle is (7,0).

The given radius of the circle is r=(3)^(1/2).

The equation of the circle is,

`\begin{gathered} (x-7)^2+(y-0)^2=(\sqrt[]{3})^2 \\ (x-7)^2+y^2=3 \end{gathered}`

Thus, the equation of the circle is (x-7)^2 +y^2 =3.