Question

two cylinders have the same volume the first cylinder has a diameter of 10 cm and a height of 30 cm The second cylinder has a diameter of 8 cm what is the height of the second cylinders the nearest tenth of a centimer

Answer 1

Given that two cylinders have the same volume but different dimension

For Cylinder 1

Diameter is 10 cm Height is 30 cm

For Cylinder 1

Diameter is 8 cm Height is h cm

The volume of a cylinder is given as;

`V=\pi r^2h`

Since the two cylinders have the same volume,

Since radius = Diameter/2

`\begin{gathered} \pi*((10)/(2))^2*30=\pi*((8)/(2))^2* h \\ \Rightarrow5^2*30=4^2* h \\ \Rightarrow h=(25*30)/(16)\approx46.9 \end{gathered}`

Hence, the second cylinder the nearest tenth of a centimeter is 46.9 cm