Question

Find the equation of line containing given points. Write the equation in slope- intercept form (0,2)(2,-3)

Answer 1

`y=(-5x)/(2)\text{ + 2}`

Step-by-step explanation:

Here, we want to get the equation of the line

The general equation of a line in slope-intercept form is:

`y\text{ = mx + b}`

where m is the slope and b is the y-intercept

We can get the equation through the following:

`(y-y_1)/(x-x_1)\text{ = }(y_2-y_1)/(x_2-x_1)`

where (x1,y1) is (0,2) and (x2,y2) is (2,-3)

Substituting the values, we have it that:

`\begin{gathered} (y-2)/(x-0)\text{ = }(-3-2)/(2-0) \\ \\ (y-2)/(x)\text{ = }(-5)/(2) \\ \\ \left(y-2\right)\text{ = }(-5x)/(2) \\ \\ y\text{ = }(-5x)/(2)\text{ + 2} \end{gathered}`