Question

Can you please help me with this question D and E

Answer 1

Part d

T= -2ºC, V=15 km/hr

We can convert to F and mi/h like this:

T= 1.8*(-2)+ 32= 28.4ºF

Ms= As/0.62= 15 km/hr /0.62= 24.19 mi/hr

Replacing we have:

`WC=35.74+0.6215\cdot(28.4)-35.75(24.19^(0.16))+0.4275(28.4)(24.19^(0.16))`

Solving we got:

`WC=35.74+17.651-59.519+20.213=14.08`

Rounded to one decimal we got:

14.1

Part e

T= 10ºC = 1.8(10)+ 32=50ºF

Ms = 34 km/hr

Ms= As/0.62= 34 km/hr/ 0.62= 54.84 mi/hr

Replacing we got:

`WC=35.74+0.6215\cdot(50)-35.75\cdot(54.84^(0.16))+0.4275(50)(54.84^(0.16))`
`WC=35.74+31.075-67.847+40.566=39.53`

Rounded to the nearest tenth we got:

39,5

Althought the reported temperature is 50 ºFahrenheit, because of wind it feels like 39.5 Fahrenheit