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What is the value of the expression when m=2 and n=-3. (4m^-3n^2)^2

1 Answer

5 votes

Giving the funtion


(4m^(-3)n^2)^2

m=2

n=-3


(4(2)^(-3)(-3)^2)^2
((4)/(2^3)(9))^2
((36)/(2^3))^2
((36^2)/(2^6))
((2^49^2)/(2^2*2^4))=(9^2)/(2^2)
(81)/(4)

then the evaluated function in m=2 n=-3

has a value of 81/4

User Vishal Thakkar
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