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Find the real zeros of f (x) =45x -5x^3

User High
by
6.7k points

1 Answer

1 vote

We will have the following:


f(x)=45x-5x^3\Rightarrow f(x)=-5x(x^2-9)
\Rightarrow f(x)=-5x(x-3)(x+3)

So, its zeros are x = -3, x = 0 & x = 3.

User Tiho
by
6.5k points
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