Question

What is the factored form of this expression?x^3 + 27(32 – 3) (3 + 35 + 9)(1 + 3) (12 - 35 + 9)(2 + 3) (1 - 3.5 + 9)(t – 3)(x2 + 3r + 9

Answer 1

We have the following:

`\begin{gathered} x^3+27 \\ x^3+3^3 \end{gathered}`

now,

`x^3+y^3=\mleft(x+y\mright)\mleft(x^2-xy+y^2\mright)`

replacing:

`x^3+3^3=\mleft(x+3\mright)\mleft(x^2-3x+9\mright)`

The answer is the secondo option