Question

Suppose that y varies directly as the square root of x, and that y = 25 when x = 289. What is y when x= 134? Round your answer to two decimal places if necessary.

Answer 1

When x = 134, y = 17.02

Step-by-step explanation

We are told that y varies directly as the square root of x.

y ∝ √x

Introducing the constant of proportionality, k

y = k√x

We are then told that

when y = 25, x = 289, with this, we can solve for k

y = k√x

25 = k × √289

25 = k × 17

25 = 17k

17k = 25

Divide both sides by 17

(17k/17) = (25/17)

k = (25/17)

We are then to solve for y when x = 134

y = k√x

y = (25/17) × √134

y = (25/17) × 11.58

y = 17.02

Hope this Helps!!!