Question

Question 13Triesremaining: 3Check for UnderstandingPoints out of2.00Write the equation of the line with a slope of 10 that goes through the point(8,-2) in Slope-Intercept and Point-Slope Form.P FlagquestionSlope-Intercept Form:Point-Slope Form:CheckPrevious page

Answer 1

`y=10x-82\rightarrow slope\text{ intercep form}`
`y+2=10x-8\rightarrow Point-SlopeForm`

Step-by-step explanation

Step 1

Let

passes throught (8,-2)

slope=20

then

a)slope -intercept form

`y-y_1=m(x-x_1)`

where

`\begin{gathered} (x_1,y_1)\text{ is a point of the line} \\ m\text{ is the slope of the line} \end{gathered}`

replace

`\begin{gathered} y-y_1=m(x-x_1) \\ y-(-2)=10(x-8) \\ y+2=10x-80 \\ \text{subtract 2 in both sides} \\ y+2-2=10x-80-2 \\ y=10x-82\rightarrow slope\text{ intercep form} \end{gathered}`

Step 2

Now, Point-Slope Form, use the same equation, but don't isolate y

`\begin{gathered} y-y_1=m(x-x_1) \\ y-(-2)=10(x-8) \\ y+2=10x-8\rightarrow Point-SlopeForm \end{gathered}`