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What is the equation of the line that is perpendicular tothe given line and passes through the point (2, 6)?108(2.6)6x = 2O x = 62-10 -8 6 -22O y = 2O y = 62468 10X1-8-4)(8.4)68-10Oh

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The line in the graph is horzontal and slope of a horizontal line is 0.

Determine the slope of perpendicular line as product of slope of perpendicular line is -1.


\begin{gathered} m=-(1)/(0) \\ =\text{undefined} \end{gathered}

The slope is undefined means line is vertical and passing through the point (2,6). So equation of line is,


x=2

Answer: x = 2

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