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Find the equation (in terms of x) of the line through the points (-4,-4) and (3,1)y=

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In order to find the equation of the line, first let's calculate its slope m using the formula below:


m=(y_2-y_1)/(x_2-x_1)

Using the given points (x1, y1) = (-4, -4) and (x2, y2) = (3, 1), we have:


m=(1-(-4))/(3-(-4))=(1+4)/(3+4)=(5)/(7)

Now, to find the equation, let's use the slope-intercept form and calculate the value of b using a given point:


\begin{gathered} y=mx+b \\ (3,1): \\ 1=(5)/(7)\cdot3+b \\ 1=(15)/(7)+b \\ b=1-(15)/(7) \\ b=-(8)/(7) \end{gathered}

Therefore the equation is y = (5/7)x - 8/7

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