we have the equation
h(t) = -16t^2 +56
Part a. How long will it take for the object to reach the water?
when the object reach teh water h(t)=0
so
For h(t)=0
solve for t
0=-16t^2+56
16t^2=56
t^2=56/16
t^2=3.5
t=(+/-)1.87
therefore
answer part a is t=1.87 sec
Remember that the time can not be negative
Part b. How will you find this characteristic?
because if the object reach the water is when the height is zero (sea level is the zero)
Part c. What is the meaning of the 56 in the equation h(t) = -16t^2 + 56?
answer is
b. The object is 56 feet above the ground initially.