Question

A bag contains 10 red 10 blue 10 green and 10 yellow M&Ms an M&M is randomly pulled from the bag and replaced seven times

Answer 1

blue

Explanation:

Answer 2

Blue

Explanation:

Given

`Red = 10`

`Blue = 10`

`Green = 10`

`Yellow = 10`

`Total = 10 + 10 + 10 + 10 = 40`

`trials = 7`

See attachment for complete question

From the attached figure;

The observed frequency of each is:

`Red = 1`

`Blue = 2`

`Green = 0`

`Yellow = 4`

Next is to calculate the probability of each of the colors.

`P(Red) = (Red)/(Total) = (10)/(10 + 10 +10 +10) =(10)/(40) = (1)/(4)`

`P(Blue) = (Blue)/(Total) = (10)/(10 + 10 +10 +10) =(10)/(40) = (1)/(4)`

`P(Green) = (Green)/(Total) = (10)/(10 + 10 +10 +10) =(10)/(40) = (1)/(4)`

`P(Yellow) = (Yellow)/(Total) = (10)/(10 + 10 +10 +10) =(10)/(40) = (1)/(4)`

The expected frequency of each is:

`Expected = Probability * trials`

So:

`Red = (1)/(4) * 7 = 1.75`

`Blue = (1)/(4) * 7 = 1.75`

`Green= (1)/(4) * 7 = 1.75`

`Yellow= (1)/(4) * 7 = 1.75`

By comparison the expected frequencies with the observed frequencies;

The closest is Blue.

Observed frequency Expected Absolute difference

`Red = 1`
`1.75`
`|1-1.75| = 0.75`

`Blue = 2`
`1.75`
`|2-1.75| = 0.25`

`Green = 0`
`1.75`
`|0-1.75| = 1.75`

`Yellow = 4`
`1.75`
`|4-1.75| = 1225`

This is so because; blue has the least absolute difference.