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Identify the diameter of⊙Q, given that A=169π2please help

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Solution:

Given that the area of circle Q is;


A=169\pi in^2

Also, the general formula is;


\begin{gathered} A=\pi r^2 \\ \\ \text{ Where }r=radius \end{gathered}

Thus, the radius, r, of the circle is;


\begin{gathered} 169\pi=\pi r^2 \\ \\ r^2=169 \\ \\ r=√(169) \\ \\ r=13in \end{gathered}

Thus, the diameter, d, is;


\begin{gathered} d=2r \\ \\ d=2(13in) \\ \\ d=26in \end{gathered}

ANSWER: The diameter of the circle is 26in

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