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Solve the system of two equations in two variables. Y=1/4x+42x - 8y =9

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The given system is


\mleft\{\begin{aligned}y=(1)/(4)x+4 \\ 2x-8y=9\end{aligned}\mright.

To solve this system, we substitute the first equation in the second one.


2x-8((1)/(4)x+4)=9

Now, we solve for x.


\begin{gathered} 2x-(8)/(4)x-32=9 \\ 2x-2x=9+32 \\ 0=41 \end{gathered}

This means the system has no solutions.

In other words, the system represents parallel lines.

User Hwatkins
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