Question

Please help me I know it’s not the second choice

Answer 1

`\begin{gathered} v_x=145\text{ m/s} \\ y=522\text{ m} \\ g=9.81m/s^2 \\ t=\text{?} \\ x=\text{?} \\ \text{For t} \\ y=(gt^2)/(2) \\ \text{Solving t} \\ 2y=gt^2 \\ t^2=(2y)/(g) \\ t=\sqrt{(2y)/(g)} \\ t=\sqrt{(2(522m))/(9.81m/s^2)} \\ t=10\text{ s} \\ \text{The time in air is 10.3 s} \\ For\text{ x} \\ x=v_xt \\ x=(145\text{ m/s})(\text{10 s}) \\ x=1450\text{ m} \\ The\text{ object falls at 1450m from it was launched} \end{gathered}`