Question

Solve log^6 (x + 1) + log^6 (x – 1) = 2.

Answer 1

`\begin{gathered} \log_6(x+1)\text{ + }\log_6(x\text{ -1\rparen = 2} \\ \\ \log_6((x+1)(x\text{ -1\rparen = 2} \\ \\ \log_6(x^2\text{ -1\rparen= 2} \\ \\ x^2\text{ - 1 =6}^2 \\ \\ x^2\text{ - 1 = 36} \\ \\ x^2=\text{ 36+1} \\ \\ x^2=\text{ 37} \\ \\ x=\text{ }\sqrt[\placeholder{⬚}]{37} \end{gathered}`