Question

If a bullet leaves the muzzle of a rifle with a speed of 600 m/s, and the barrel of the rifle is 0.800 m long, at what rate is the bullet accelerated while in the barrel?That is the question I am having trouble with

Answer 1

Given that the final velocity of the bullet is

`V_f=600\text{ m/s}`

The initial velocity of the bullet is

`V_i=0\text{ m/s}`

The distance traveled by the bullet is x = 0.8 m

We have to find the acceleration.

Let the acceleration be denoted by a.

The equation which can be used to calculate acceleration is

`(V_f)^2-(V_i)^2=2ax`

Substituting the values, acceleration will be

`\begin{gathered} (600)^2-0^2=2* a*0.8 \\ a=(360000)/(1.6) \\ =225000m/s^2 \end{gathered}`

Thus the acceleration will be 225000 m/s^2.