Question

Find the slope, m of the line that passes through the points 3 83 - .) and (1) 6. -5 16' 6 Enter your answer as a fraction in simplest form in the box.

Answer 1

Given:

The points on the line are,

`((3)/(8),-(1)/(4))\text{ and (-}(5)/(16),(1)/(6))`

The slope of the line is calculated as,

`\begin{gathered} m=(y_2-y_1)/(x_2-x_1) \\ (x_1,y_1)=((3)/(8),-(1)/(4)) \\ (x_2,y_2)=\text{(-}(5)/(16),(1)/(6)) \\ m=((1)/(6)-(-(1)/(4)))/(-(5)/(16)-(3)/(8)) \\ m=((2)/(6*2)+(3)/(4*3))/(-(5)/(16)-(3*2)/(8*2)) \\ m=((2+3)/(12))/((-5-6)/(16)) \\ m=(5)/(12)*(16)/(-11) \\ m=-(20)/(33) \end{gathered}`

Answer: slope is -20/33