Question

Find the slope and y-intercept of the line. Graph the line.

Answer 1

Graphing the equation we have;

Step-by-step explanation:

Given the equation;

`x+5y=40`

the slope of the line can be derived by expressing the equation in slope-intercept form;

`\begin{gathered} 5y=-x+40 \\ y=-(1)/(5)x+(40)/(5) \\ y=-(1)/(5)x+8 \end{gathered}`

So, the slope and y-intercept are;

`\begin{gathered} \text{slope m = -}(1)/(5) \\ y-\text{intercept b = 8} \end{gathered}`

to graph the equation, let us find the x-intercept;

`\begin{gathered} at\text{ y=0;} \\ x+5y=40 \\ x+0=40 \\ x=40 \\ (40,0) \\ at\text{ x=0;} \\ (0,8) \end{gathered}`

Graphing the equation we have;

Other points on the graph includes;

`\begin{gathered} at\text{ x=10}; \\ y=-(1)/(5)(10)+8=-2+8=6 \\ (10,6) \\ at\text{ x=20;} \\ y=-(1)/(5)(20)+8=-4+8=4 \\ (20,4) \end{gathered}`