Question

2. A force of 600 Newtons acts on a ball for 1.5 seconds after being hit by a volleyball player.

a. What is the change in momentum of the ball?

b. If the ball has a mass of 275 grams, what is its velocity?

Answer 1

a) Data:

F = 600 N

t = 1.5 s

The equation for Impulse:

Impulse = I = F x t,

then the change in momentum: pf - pi

Impulse and the change in momentum are related like this:

pf - pi = I = F x t = 600 N x 1.5 s = 900 N.s

Therefore the change in momentum: pf-pi = 900 N.s

b) Velocity (t) = initial velocity + a x t

We can assume initial velocity = 0 m/s

From F = m x a = mass x acceleration, we clear "a",

m = 275 g = 0.275 kg (1 kg = 1000 g)

Then, F/m = a => 600 N/0.275 kg = 2182 m/s^2

Velocity (t) = 0 + 2182 m/s^2 x 1.5 s = 3273 m/s

Velocity = 3273 m/s