Question

What is the concentration if I have 450 mL of iron (II) chloride (FeCl2) solution that contains9.6 grams of iron (II) chloride solute?

Answer 1

Answer;

0.168M

Explanations:

The formula for calculating the concentration of the solution is expressed as:

`concentration=(mole)/(volume)`

Determine the moles of iron(II) chloride

`\begin{gathered} mole\text{ of FeCl}_2=\frac{9.6g}{126.751g\text{/}mol} \\ mole\text{ of FeCl}_2=0.0757moles \end{gathered}`

Given that volume is 0.45L, hence the concentration is expressed as:

`\begin{gathered} concentration=(0.0757)/(0.45) \\ concentration=0.168M \end{gathered}`

Hence the concentration of the solution is 0.168M