Question

I have this homework i need help with ?Part (a)

Answer 1

Given that the mass of train is

`m=\text{ }8.12*10^6\text{ kg}`

The deceleration of the train is

`\begin{gathered} a\text{ = -104 km/h} \\ =-104*(5)/(18) \\ =\text{ -28.88 m/s} \end{gathered}`

The braking force can be calculated by the formula

`F=ma`

Substituting the values, the braking force will be

`\begin{gathered} F=8.12*10^6*(-28.88) \\ =2.348*10^8\text{ N} \end{gathered}`

Thus, the braking force is 2.348 x 10^8 N.