Question

Advanced Wireless Services (AWS) is a wireless telecommunications spectrum band used for mobile voice and data services, video, and messaging. The AWS band uses frequencies in several segments: from 1695 to 2200 MHz. a) Determine the corresponding range of wavelengths used by the AWS mobile devices. b) To what region/band of electromagnetic spectrum does the range belong

Answer 1

The wavelength range for AWS is approximately 0.136 to 0.177 meters, which falls within the microwave region of the electromagnetic spectrum, commonly used for wireless communication technologies.

Step-by-step explanation:

To determine the range of wavelengths used by Advanced Wireless Services (AWS) devices, we can apply the formula for the speed of light:

c = λf

where c is the speed of light in a vacuum (approximately 3 x 108 m/s), λ is the wavelength in meters, and f is the frequency in hertz. Given the AWS frequencies range from 1695 to 2200 MHz (which is 1.695 x 109 to 2.2 x 109 Hz), we can calculate the corresponding wavelength range as follows:

λ = c / f

For the lower frequency (1.695 GHz): λ = 3 x 108 m/s / 1.695 x 109 Hz ≈ 0.177 meters

For the higher frequency (2.2 GHz): λ = 3 x 108 m/s / 2.2 x 109 Hz ≈ 0.136 meters

Therefore, the range of wavelengths for AWS is approximately 0.136 to 0.177 meters.

As for part b, the range of frequencies used by AWS falls within the microwave region of the electromagnetic spectrum, which is commonly used for wireless communication technologies like Wi-Fi, GPS, and cellular signals. Microwaves range from about 1 to 100 GHz, which corresponds to wavelengths of 0.3 m to 3 mm.

Answer 2

Given data

*The given frequency is

`f_1_{}=1695\text{ MHz}=1695*10^6\text{ Hz}`

*The another given frequency is

`f_2=2200\text{ MHz=}2200*10^6\text{ Hz}`

*The given speed of light is c = 3.0 × 10^8 m/s

(a)

The formula for the wavelength is given as

`\lambda_1=(c)/(f_1)`

Substitute the known values in the above expression as

`\begin{gathered} \lambda_1=\frac{(3*10^8)}{(1695*10^6)^{}} \\ =0.176\text{ m} \end{gathered}`

The another wavelength for the another frequency is calculated as

`\begin{gathered} \lambda_2=(c)/(f_2) \\ =((3.0*10^8))/((2200*10^6)) \\ =0.136\text{ m} \end{gathered}`

(b)

Radio spectrum is an electromagnetic spectrum where the frequency range belongs of wireless telecommunication.