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1) 42,58, 67,55, 40, 69, 66, 51, 46, 48, 68 Minimum : Q: Q2: Q, Maximum :

User ThantiK
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1 Answer

4 votes

EXPLANATION

Minimum

The first Quartile is the value separating the lower quarter and higher three - quarters of the data set.

The first quartile is computed by taking the median of the lower half of a sorted set.

Arranging terms in ascending order

40, 42 , 46, 48, 51, 55, 58, 66, 67, 68, 69

Here, we can see that:

Minimum = 40

Maximum = 69

Q2=55 (median)

Taking the lower half of the ascending set:

Counting the number of terms in the data set:

{40, 42 , 46, 48, 51, 55, 58, 66, 67, 68, 69}

{1, 2 , 3, 4, 5, 6, 7, 8, 9, 10, 11}

The number of terms in the data set is:

11

Since the number of terms is odd, take the elements below the middle one, that is, the lower 5 elements.

40, 42 , 46, 48, 51

Median of 40, 42 , 46, 48, 51:

The number of terms in the data set is 5.

Since the number of terms is odd, the median is the middle element of the sorted set.

Q1: 46

------------------------------------

Q3:

Since the number of terms is odd, take the elements above the middle one, that is, the upper 5 elements.

58, 66, 67, 68, 69

The number of terms in the data set is

5

Since the number of terms is odd, the median is the middle element of the sorted set.

Q3=67

------------------------------------------------------------------------------------

Interquartile Range:

The interquartile range is the difference of the first and third quartiles

We have that:

Q1=46

Q3=67

Computing the difference between 67 and 46:

67-46= 21

Interquartile Range=21

-------------------------------

Answers:

Minimum = 40

Q1=46

Q2=55 (median)

Q3=67

Maximum = 69

Interquartile Range=21

User Niran Manandhar
by
7.2k points

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