221k views
3 votes
A coil of 17.771 H carries a current of 11.121 A. Compute the energy stored .

User Dis
by
6.4k points

1 Answer

5 votes

Given

The inductance is H=17.771 H

Current is , I=11.121A

To find

The energy stored

Step-by-step explanation

The energy stored is given by


E=(1)/(2)LI^2

Putting the values,


\begin{gathered} E=(1)/(2)*17.771*(11.121)^2 \\ \Rightarrow E=1098.92J \end{gathered}

Conclusion

The energy stored is 1098.92J

User Sharvey
by
7.0k points