Question

A coil of 17.771 H carries a current of 11.121 A. Compute the energy stored .

Answer 1

Given

The inductance is H=17.771 H

Current is , I=11.121A

To find

The energy stored

Step-by-step explanation

The energy stored is given by

`E=(1)/(2)LI^2`

Putting the values,

`\begin{gathered} E=(1)/(2)*17.771*(11.121)^2 \\ \Rightarrow E=1098.92J \end{gathered}`

Conclusion

The energy stored is 1098.92J