Question

Question 2b: NAME THE Y-INTERCEPTy = -2(x - 3)^2

Answer 1

The given equation corresponds to a parabola:

`y=-2(x-3)^2`

The y-intercept of the parabola is the point when it crosses the y-axis, at this point x=0, to determine this value you have to replace the formula with x=0 and calculate the value of y:

`\begin{gathered} y=-2(0-3)^2 \\ y=-2(-3)^2 \end{gathered}`

Solve the exponent first, then the multiplication

`\begin{gathered} y=-2(-3)^2 \\ y=-2\cdot9 \\ y=-18 \end{gathered}`

The y-intercept for the given function is (0,-18)