From the given equation and the given table, let the missing are m and b
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
To find them use two points from the table
Let us use point (0, -2)
![\begin{gathered} x=0,y=-2 \\ -2=m(0)+b \\ -2=0+b \\ -2=b \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/sltji86vafq3hpt2wqpi3akb1a43snaakv.png)
Substitute b in the equation by -2
![\begin{gathered} y=mx+(-2) \\ y=mx-2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/hg385hj4ehuf8i36giupkufnl6qpfarmul.png)
Now, use the point (1, 1) to find m
![\begin{gathered} 1=m(1)-2 \\ 1=m-2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1drurkcqthb63djkhlklhiu0vyjtx9nung.png)
Add 2 to both sides
![\begin{gathered} 1+2=m-2+2 \\ 3=m \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/dmnbjlyrx5dadwnyrobivjatfyv3fz2opq.png)
Substitute m by 3 in the equation, then
The equation is
![\begin{gathered} y=3x-2 \\ y=3x+(-2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/k6qrcjbjt11nc6su1j3yo4tsg0fxjl26l1.png)
The answer is y = 3x + (-2)
The missings are 3