Question

What is the inverse equation for h(x) = 2log(x-3) ?

Answer 1

Given the function:

`h(x)=2log\left(x-3\right)`

To find its inverse:

`\begin{gathered} y=2log\left(x-3\right) \\ x=2log\left(y-3\right) \end{gathered}`

solving for y:

`(x)/(2)=log(y-3)`
`\begin{gathered} 10^{(x)/(2)}=y-3 \\ \\ 10^{(x)/(2)}+3=y \end{gathered}`

ANSWER