Question

Predict the formula for each ionic compoundbarium sulfate:lithium nitrate :cesium sulfide:

Answer 1

INFORMATION:

We have the following ionic compounds:

- barium sulfate

- lithium nitrate

- cesium sulfide

And we must write their formulas

STEP BY STEP EXPLANATION:

1. Barium sulfate:

To write its formula, we need to use that:

- the element symbol for Barium is Ba, and it has a charge of 2+

- in the given table, sulfate is a polyatomic ion represented by SO4, and it has a charge of 2-

Now, we must add up the charges to verify if the ionic compound is neutral

`2^++2^-=0`

Since the compound has a net charge of zero, we can write its formula as

`BaSO_4`

2. Lithium nitrate:

To write its formula, we need to use that:

- the element symbol for Lithium is Li, and it has a charge of 1+

- in the given table, nitrate is a polyatomic ion represented by NO3, and it has a charge of 1-

Now, we must add up the charges to verify if the ionic compound is neutral

`1^++1^-=0`

Since the compound has a net charge of zero, we can write its formula as

`LiNO_3`

3. Cesium sulfide:

To write its formula, we need to use that:

- the element symbol for Cesium is Cs, and it has a charge of 1+

- the element symbol for sulfide is S, and it has a charge of 2-

Now, we must add up the charges to verify if the ionic compound is neutral

`1^++2^-=1^-`

Since the compound has a net different from zero, we need to analyze the compound.

So, if we have just one atom of Cs, the charge would be 1+, but if we take two atoms the charge would be 2(1+) = 2+

Now, verifying the net charge

`2^++2^-=0`

Now, we can write its formula as

`Cs_2S`

ANSWER:

barium sulfate:

`BaSO_4`

lithium nitrate :

`LiNO_3`

cesium sulfide:

`Cs_2S`