Question

You pick a card at random. Without putting the first card back, you pick a second card at rando 4 5 6. What is the probability of picking an odd number and then picking an odd number? Simplify your answer and write it as a fraction or whole number.

Answer 1

Given data:

The three numbers on the cards are 4, 5, 6.

The probability of picking an odd number and then picking an odd number is,

`\begin{gathered} P=(1)/(3)*(0)/(2) \\ =0 \end{gathered}`

Thus, the probability of picking an odd number and then picking an odd number is 0.