Question

In the diagram below, quadrilateral ABCD is inscribed in circle P.What is m< DCB?

Answer 1

A) 70º

Step-by-step explanation

In quadrilaterals inscribed in a circle, opposite angles are supplementary - their measures add up 180º. Therefore:

`\begin{gathered} m\angle DAB+m\angle DCB=180º \\ 110º+m\angle DCB=180º \\ m\angle DCB=180º-110º \\ m\angle DCB=70º \end{gathered}`