Question

The sum of three consecutive numbers is one hundred five.What is the smallest of the three numbers

Answer 1

For this problem we know that the sum of 3 consecutive numbers is one hundred five. Let's assume that the 3 numbers is: a, a+1, a+2

And we can set up the following equation:

`a+(a+1)+(a+2)=105`

And we can solve for a like this:

`3a+3=105`

We can subtract 3 in both sides and we got:

`3a=102`

And we can divide both sides by 3 and we got:

`a=(102)/(3)=34`

And we can conclude that the smallest number is 34