Question

What is the probability of meeting at least one person with the flu in twelve random encounters on campus when the infection rate is 8%

Answer 1

`p(x)=(0.08)^x(0.92)^(12-x)`

The probability of at least one person is;

`\begin{gathered} 1-p(0)=1-(0.08)^0(0.92)^(12-0) \\ \\ =0.6323 \end{gathered}`