First, let's calculate the total amount of coins:
![7+2+1=10](https://img.qammunity.org/2023/formulas/mathematics/college/7qtze9bus1ypa3gdwzk406jtn4u8ajkix4.png)
Since there are 7 pennies among the 10 coins, the probability of picking a penny is:
![P_1=(7)/(10)](https://img.qammunity.org/2023/formulas/mathematics/college/u8rb0a7idl15bh52erov8oa5lcwrazamfv.png)
Then, there will be 9 coins, from which only 1 is a dime, so the probability of the second pick being a dime is:
![P_2=(1)/(9)](https://img.qammunity.org/2023/formulas/mathematics/college/8w3tz0cbhg1ceket9gddji50e3mytdqc0h.png)
Now, to calculate the final probability, let's multiply both probabilities above:
![\begin{gathered} P=P_1\cdot P_2 \\ P=(7)/(10)\cdot(1)/(9) \\ P=(7)/(90) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1cnom5pblqf7c0vq8enuinzsciswisqste.png)
Therefore the probability is 7/90.