Question

Solve the equation for all values of x by completing the squarex²-12x=-23

Answer 1

We can do the following:

`x^2-12x+((12)/(2))^2=-23+((12)/(2))^2`

And if we simplify we got.

`x^2-12x+36=-23+36`
`(x-6)^2=13`

Taking square root we got:

`x-6=\pm\sqrt[]{13}`

Then the two solutions are:

`x_1=-\sqrt[]{13}+6,x_2=\sqrt[]{13}+6`