Question

Consider the following distribution of data from a college survey.icted in JEAndroid Usersthey arepercentageom peaksased on telred 18 andiPhone UsersAges 18 - 30Total4056531058Ages 31 – 406875381225Ages 41 - 5010683911459nfidencTotal216015823742-5'e an(Write all answers as a percentage without the % symbol to 1 decimal.) tu tornilleWhat is the probability that someone chosen at random was aged 41 - 50?나200

Answer 1

We need to calculate probabilities with the data in the table.

What is the probability that someone chosen at random was aged 41-50?

`\text{prob}=\frac{succes\text{s cases}}{total\text{ cases}}=(1459)/(3742)\approx0.39`

The probability is 39%.

What is the probability that someone chosen at random was an Android user or aged 41-50?

`\begin{gathered} \text{prob}=\frac{success\text{ cases}}{total\text{ cases}}=(1459+2160-1068)/(3742) \\ \text{prob}=(2551)/(3742)\approx0.682 \end{gathered}`

The probability is 68.2%.

What is the probability that someone being aged 41-50 and an Android user?

`\text{prob}=\frac{success\text{ cases}}{total\text{ cases}}=(1068)/(3742)\approx0.285`

The probability is 28.5%.

Given a random person was aged 18-30, what is the probability that they were and iPhone user?

`\text{prob}=\frac{success\text{ cases}}{total\text{ cases}}=(653)/(1058)=0.617`

The probability is 61.7 %.