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3. A new Outdoor Recreation Center is being built in Del Rio. The perimeter of the rectangular playing field is 374 yards. Thelength of the field is 5 yards less than triple the width. What are the dimensions of the playing field?The width isyards.The length isyards.?

1 Answer

2 votes

The perimeter of a rectangle is given by the formula


P=2L+2W

where

L is the length

W is the width

In this problem

we have that

P=374 yd

L=3W-5

substitute the given values in the formula


374=2(3W-5)+2W

Solve for W


\begin{gathered} 374=6W-10+2W \\ 374=8W-10 \\ 8W=384 \\ W=48\text{ yd} \end{gathered}

Find out the value of L


\begin{gathered} L=3(48)-5 \\ L=139\text{ yd} \end{gathered}

therefore

The length is 139 yards

The width is 48 yards

User Abhishek Jadhav
by
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