Question

of the 41 plays attributed to a playwright, 12 are comedies, 18 are tragedies, and 11 are histories. If one play is selected at random, find the odds in favor ofselecting a history or a tragedyThe odds in favor are 10(Simplify your answer.)

Answer 1

Step 1:

The odds in favor - the ratio of the number of ways that an outcome can occur compared to how many ways it cannot occur. Odds in favor = Number of successes: Number of failures. The odds against - the ratio of the number of ways that an outcome cannot occur compared to in how many ways it can occur.

Step 2

Comedy = 12

Tragedy = 18

History = 11

Step 3

The odds in favor of selecting a history or a tragedy

`\begin{gathered} \text{= }\frac{11\text{ + 18}}{41\text{ - 11 - 18}} \\ =\text{ }(29)/(12) \end{gathered}`

Final answer

`(29)/(12)`