Given:
The mass of the Jupiter, M=1.90×10²⁷ kg
The radius of the Jupiter, R=7.15×10⁷ m
To find:
The magnitude of the acceleration due to gravity on Jupiter.
Step-by-step explanation:
The gravitational field strength is given by the formula,
![g=(GM)/(R^2)](https://img.qammunity.org/2023/formulas/physics/college/ejy1b3d15ahsxrgmfsg96r54s28rdfseyb.png)
Where G is the gravitational constant.
On substituting the known values,
![\begin{gathered} g=(6.67*10^(-11)*1.90*10^(27))/((7.15*10^7)^2) \\ =24.8\text{ m/s}^2 \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/9fkqqgthf6xqnq17z8xgd28l6jw8dqny35.png)
Final answer:
The acceleration due to gravity on Jupiter is 24.8 m/s²