Let's begin by listing out the information given to us:
MARILYN (total, t) = 7 letters
At random implies every letter has an equal chance of being chosen
Number of trials (r) = 5 times
Number of "M" (n) = 1
Probability of choosing "M" once is given by:
![P=(n)/(t)=(1)/(7)](https://img.qammunity.org/2023/formulas/mathematics/college/6jzo10y8duarxr21tt0lrdlkvglq8qfpin.png)
what is the probability that the M is chosen exactly three times in five separate trials?
Of the 5 trials: 3 times "M" is picked, 2 times "other letters" are picked
![\begin{gathered} P=((n)/(t))^r\Rightarrow P=((1)/(7))^3\cdot((6)/(7))^2 \\ P=(1)/(343)\cdot(36)/(49)=(36)/(16807) \\ P=(36)/(16807)=0.002142\approx0.0021 \\ P=0.0021 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/x50uvgzvravwc2sotn44o0e5zcp1tzku4a.png)