Question

Use the discriminant b^2 - 4ac, to determine the number of solutions of the following equation. x^2 = - 5Then solve the quadratic equation using the Formula X (FORMULA is in the pic attached)

Answer 1

`\begin{gathered} x^2=-5 \\ x^2+5=0 \\ On\text{ this case} \\ a=1 \\ b=0 \\ c=5 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \\ x=\frac{0\pm\sqrt[]{0^2-4(1)(5)}}{2(1)} \\ \\ \pm\sqrt[]{0^2-4(1)(5)} \\ \pm\sqrt[]{0^{}-20} \\ \pm\sqrt[]{-20} \\ \text{ ---this function has two non-real solutions}--- \end{gathered}`