Question

What is the angle of the 2nd order bright fringe produced by two slits that are 8.25x10-5m apart if the wavelength of the incident light is 4.50x10-7m?0.0109⁰0.625°91.7°1.60⁰

Answer 1

In order to calculate the angle, we can use the formula below for a constructive interference (the interference is constructive because the fringe is bright):

`d\sin\theta=m\lambda`

Where d is the distance between the slits, m is the order of the interference and lambda is the wavelength.

So, using d = 8.25 * 10^-5, m = 2 and lambda = 4.5 * 10^-7, we have:

`\begin{gathered} 8.25\cdot10^(-5)\cdot\sin\theta=2\cdot4.5\cdot10^(-7)\\ \\ \sin\theta=(9\cdot10^(-7))/(8.25\cdot10^(-5))\\ \\ \sin\theta=1.091\cdot10^(-2)\\ \\ \theta=0.625° \end{gathered}`

Therefore the correct option is the second one.