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solve the volume of a cone, V=1/3πr^2h, for h.h = ?basically like v=lwh, for h. and h = v over lw (v/lw)

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\begin{gathered} V=(1)/(3)r^2h\pi \\ \text{Solving for h:} \\ \text{Multiply both sides by 3:} \\ 3V=3\cdot(1)/(3)r^2h\pi \\ 3V=r^2h\pi \\ \text{Divide both sides by }r^2\pi \\ (3V)/(r^2\pi)=(r^2h\pi)/(r^2\pi) \\ (3V)/(r^2\pi)=h \\ \\ h=(3V)/(r^2\pi) \end{gathered}

User Whit Waldo
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